Log(6x)-log^1+x=3

Solution for Log(6x)-log^1+x=3 equation:

Simplifying
Log(6x) + -1log + x = 3

Remove parenthesis around (6x)
goL * 6x + -1log + x = 3

Reorder the terms for easier multiplication:
6goL * x + -1log + x = 3

Multiply goL * x
6goxL + -1log + x = 3

Reorder the terms:
-1glo + 6goxL + x = 3

Solving
-1glo + 6goxL + x = 3

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1x' to each side of the equation.
-1glo + 6goxL + x + -1x = 3 + -1x

Combine like terms: x + -1x = 0
-1glo + 6goxL + 0 = 3 + -1x
-1glo + 6goxL = 3 + -1x

Reorder the terms:
-3 + -1glo + 6goxL + x = 3 + -1x + -3 + x

Reorder the terms:
-3 + -1glo + 6goxL + x = 3 + -3 + -1x + x

Combine like terms: 3 + -3 = 0
-3 + -1glo + 6goxL + x = 0 + -1x + x
-3 + -1glo + 6goxL + x = -1x + x

Combine like terms: -1x + x = 0
-3 + -1glo + 6goxL + x = 0

The solution to this equation could not be determined.